『PHP』Invalid argument supplied for foreach 解决办法
1 QUOTE: 2 foreach($extcredits as $id => $credit) 3 { 4 if($credit['ratio']) 5 { 6 $exchcredits[$id] = $credit; 7 } 8 } 9 改为 10 11 QUOTE: 12 if(is_array($extcredits)) //add 13 { 14 foreach($extcredits as $id => $credit) 15 { 16 if($credit['ratio']) 17 { 18 $exchcredits[$id] = $credit; 19 } 20 } 21 } //add
- 上一篇 »php foreach引用赋值
- 下一篇 »PHP中非常全面的乱码解决方案