一个简单的jQuery插件ajaxfileupload实现ajax上传文件例子
页面代码：
<html>
<!-- 引入相关的js文件，相对路径 -->
<script type="text/javascript" src="js/jquery.js"></script>
<script type="text/javascript" src="js/ajaxfileupload.js"></script>
<!-- 执行上传文件操作的函数 -->
<script type="text/javascript">
function ajaxFileUpload(){
$.ajaxFileUpload(
{
url:'update.do?method=uploader', //需要链接到服务器地址
secureuri:false,
fileElementId:'houseMaps', //文件选择框的id属性
dataType: 'xml', //服务器返回的格式，可以是json
success: function (data, status) //相当于java中try语句块的用法
{
$('#result').html('添加成功');
},
error: function (data, status, e) //相当于java中catch语句块的用法
{
$('#result').html('添加失败');
}
}
);
}
</script>
</head>
<body>
<form method="post" action="update.do?method=uploader" enctype="multipart/form-data">
<input type="file" />
<input type="button" value="提交" onclick="ajaxFileUpload()"/>
</form>
<div ></div>
</body>
</html>
服务器代码：
public class UpdateAction extends DispatchAction {
public ActionForward uploader(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
UpFormForm upFormForm = (UpFormForm) form;
FormFile ff = upFormForm.getHouseMaps();
try {
InputStream is = ff.getInputStream();
File file = new File("D:/" + ff.getFileName()); //指定文件存储的路径和文件名
OutputStream os = new FileOutputStream(file);
byte[] b = new byte[1024];
int len = 0;
while((len = is.read(b)) != -1){
os.write(b, 0, len);
}
os.close();
is.close();
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
}
