c# asp.net 多数组索引的解决方法
本人今天做了一个功能 需要在一个类里用多个数组，
数组需要索引器来调用 一个数组
我查了msdn 一个类里面只能有一个this 索引器
那这么多数组如何构造索引呢
我在坛子里找到了解决之道
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using System;
namespace TestUse
{
/// <summary>
/// Summary description for Muliti.
/// </summary>
public class Muliti
{
public Muliti()
{
//
// TODO: Add constructor logic here
//
}
private string[] test1;
private object[] test2;
private int[] test3;
public object this[string arrname,int index]{
get{
switch(arrname){
case "test1":return test1[index];
case "test2":return test2[index];
case "test3":return test3[index];
default:return null;
}
}
set{
switch(arrname)
{
case "test1":test1[index]=value.ToString();break;
case "test2":test2[index]=value;break;
case "test3":test3[index]=(int)value;break;
default:break;
}
}
}
public void setUpArray(){
test1 = new string[3];
test2 = new object[2];
test3 = new int[4];
}
}
}
using System;
namespace TestUse
{
/// <summary>
/// Summary description for Muliti.
/// </summary>
public class Muliti
{
public Muliti()
{
//
// TODO: Add constructor logic here
//
}
private string[] test1;
private object[] test2;
private int[] test3;
public object this[string arrname,int index]{
get{
switch(arrname){
case "test1":return test1[index];
case "test2":return test2[index];
case "test3":return test3[index];
default:return null;
}
}
set{
switch(arrname)
{
case "test1":test1[index]=value.ToString();break;
case "test2":test2[index]=value;break;
case "test3":test3[index]=(int)value;break;
default:break;
}
}
}
public void setUpArray(){
test1 = new string[3];
test2 = new object[2];
test3 = new int[4];
}
}
}
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private void button1_Click(object sender, System.EventArgs e)
{
Muliti testm = new Muliti();
testm.setUpArray();
testm["test1",0]="test1-0";
testm["test2",0]= "test2-0";
testm["test3",0]= 3;
MessageBox.Show((string)testm["test1",0]);
MessageBox.Show((string)testm["test2",0]);
MessageBox.Show("" + testm["test3",0]);
}
private void button1_Click(object sender, System.EventArgs e)
{
Muliti testm = new Muliti();
testm.setUpArray();
testm["test1",0]="test1-0";
testm["test2",0]= "test2-0";
testm["test3",0]= 3;
MessageBox.Show((string)testm["test1",0]);
MessageBox.Show((string)testm["test2",0]);
MessageBox.Show("" + testm["test3",0]);
}
这样 加个判断就行了 有时候头脑还真的迷糊 想了半天还是没想起来。