Go语言学习笔记,四

10.字符串原理解析

a.字符串底层就是一个byte数组,所以可以和[]byte类型互相转换

b.字符串之中的字符是不能修改的,想要修改只能用byte切片来修改

  1: package main
  2: 
  3: import (
  4:     "fmt"
  5: )
  6: 
  7: func testString(){
  8:     var str string = "hello"
  9:     fmt.Printf("str[0]=%c len(str)=%d\n", str[0], len(str))
 10:     for index, val := range str {
 11:             fmt.Printf("str[%d]=%c\n", index, val)
 12:     }
 13:     // 定义byte切片
 14:     var byteSlice []byte
 15:     byteSlice = []byte(str)
 16:     byteSlice[0] = 'o'
 17:     str = string(byteSlice)
 18:     fmt.Println(str)
 19: }
 20: 
 21: func main()  {
 22:     testString()
 23: }

c.字符串是byte字节组成,所以字符串的长度是byte字节的长度

d.rune类型用来表示utf8字符,一个rune字符由1个或多个byte组成

  1: var b rune = '中'
  2:     str = "中文123"
  3:     fmt.Printf("b=%c\n", b)
  4:     var runeSlice []rune
  5:     runeSlice = []rune(str)
  6:     fmt.Printf("str长度=%d len(str)=%d\n", len(runeSlice), len(str))

几个关于字符串的练习:

test1:对英文字符串进行逆序

  1: func test1(){
  2:     var str = "hello"
  3:     // var bytes []byte = []byte(str)
  4:     bytes := []byte(str)
  5:     for i :=0; i < len(str)/2; i++ {
  6:             tmp := bytes[len(str)-i-1]
  7:             bytes[len(str)-i-1] = bytes[i]
  8:             bytes[i] = tmp
  9:     }
 10:     str = string(bytes)
 11:     fmt.Println(str)
 12: }

test2:对包含中文的字符串进行逆序

  1: func test2(){
  2:     var str = "hello,你好"
  3:     runes := []rune(str)
  4: 
  5:     for i:=0; i < len(runes)/2; i++ {
  6:             tmp := runes[len(runes)-i-1]
  7:             runes[len(runes)-i-1] = runes[i]
  8:             runes[i] = tmp
  9:     }
 10:     str = string(runes)
 11:     fmt.Println(str)
 12: }

test3:判断一个字符串是否是回文

  1: func test3() {
  2:     var str = "上海自来水来自海上"
  3:     runes := []rune(str)
  4:     for i:=0; i < len(runes)/2; i++ {
  5:             tmp := runes[len(runes)-i-1]
  6:             runes[len(runes)-i-1] = runes[i]
  7:             runes[i] = tmp
  8:     }
  9:     str_2 := string(str)
 10:     if str == str_2 {
 11:             fmt.Println("yes")
 12:     }else{
 13:             fmt.Println("no")
 14:     }       
 15: }