python 比较列表相邻元素,找相同或去重

python 列表去除相邻重复相等数据(只保留一个)

参开资料:https://stackoverflow.com/questions/3460161/remove-adjacent-duplicate-elements-from-a-list

1 In [1]: import itertools                                                        
2 
3 In [2]: a=[0, 1, 3, 2, 4, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 16, 17, 18, 18, 19, 20, 20, 21, 22, 22, 22, 23, 23, 23, 26, 29, 29, 30, 32, 33, 34, 32, 32, 15, 24]    
4 
5 In [3]: b=[k for k, _ in itertools.groupby(a)]                                  
6 
7 In [4]: print(b)                                                                
8 [0, 1, 3, 2, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20, 21, 22, 23, 26, 29, 30, 32, 33, 34, 32, 15, 24]

python 列表找到相邻元素相同的元素值(理解了 m=a[1:] n=a[:-1] 得到的就是要比较的前后数据之后,你就可以轻松地做玩转相邻元素啦)

参考资料:https://stackoverflow.com/questions/23452422/how-to-compare-corresponding-positions-in-a-list

 1 In [22]: import numpy as np                                                                                                                                             
 2 
 3 In [23]: a=[0, 1, 3, 2, 4, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 16, 17, 18, 18, 19, 20, 20, 21, 22, 22, 22, 23, 23, 23, 26, 29, 29, 30, 32, 33, 34, 32, 32, 15, 24]   
 4 
 5 In [24]: m=a[1:]                                                                                                                                                        
 6 
 7 In [25]: n=a[:-1]                                                                                                                                                       
 8 
 9 In [26]: len(a)                                                                                                                                                         
10 Out[26]: 41
11 
12 In [27]: len(m)                                                                                                                                                         
13 Out[27]: 40
14 
15 In [28]: len(n)                                                                                                                                                         
16 Out[28]: 40
17 
18 In [29]: c=[i[0]==i[1] for i in zip(m, n)]                                                                                                                              
19 
20 In [30]: print(c)                                                                                                                                                       
21 [False, False, False, False, True, False, False, False, False, False, False, False, False, False, False, True, False, False, True, False, False, True, False, False, True, True, False, True, True, False, False, True, False, False, False, False, False, True, False, False]
22 
23 In [31]: d=np.array(a[:-1])[c]                                                                                                                                          
24 
25 In [32]: print(d)                                                                                                                                                       
26 [ 4 16 18 20 22 22 23 23 29 32]
27 
28 In [33]: result = list(set(d))                                                                                                                                          
29 
30 In [34]: result                                                                                                                                                         
31 Out[34]: [32, 4, 16, 18, 20, 22, 23, 29]

也可以用以下的方法比较出相邻元素是否相等,即求出上面的变量 c,然后再执行后面的步骤

参考资料:https://stackoverflow.com/questions/36343688/check-if-any-adjacent-integers-in-list-are-equal

 1 In [35]: import operator                                                        
 2 
 3 In [36]: import itertools                                                       
 4 
 5 In [37]: c2=list(map(operator.eq, a, itertools.islice(a, 1, None)))             
 6 
 7 In [38]: print(c2)                                                              
 8 [False, False, False, False, True, False, False, False, False, False, False, False, False, False, False, True, False, False, True, False, False, True, False, False, True, True, False, True, True, False, False, True, False, False, False, False, False, True, False, False]
 9 
10 In [39]: c==c2                                                                  
11 Out[39]: True