[LeetCode][JavaScript]Compare Version Numbers

Compare Version Numbers

Compare two version numbers version1 and version2.

If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.

The . character does not represent a decimal point and is used to separate number sequences.

For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

https://leetcode.com/problems/compare-version-numbers/

恶心题，看我给的几个Test Case吧。

 1 /**
 2  * @param {string} version1
 3  * @param {string} version2
 4  * @return {number}
 5  */
 6 var compareVersion = function(version1, version2) {
 7     var v1Arr = version1.split('.');
 8     var v2Arr = version2.split('.');
 9     var len = Math.max(v1Arr.length, v2Arr.length);
10     for(var i = 0; i < len; i++){
11         var v1 = format(v1Arr[i]);
12         var v2 = format(v2Arr[i]);
13         if(v1 > v2){
14             return 1;
15         }else if(v1 < v2){
16             return -1;
17         }
18     }
19     return 0;
20 
21     function format(num){
22         if(!num){
23             return 0;
24         }
25         var res = parseInt(num);
26         if(isNaN(res)){
27             res = 0;
28         }
29         return res;
30     }
31 };
32 
33 function test(){
34     console.log(compareVersion('1','0')); //1
35     console.log(compareVersion('1.2','1.10'));  //-1
36     console.log(compareVersion('1.1','1.10'));  //-1
37     console.log(compareVersion('01','1')); // 0
38     console.log(compareVersion('1.0.0.0.0.0.0','1.0.0'));  // 0
39 }