java POI HTML转Word 两种方式

说明,不论使用哪种方式,都不能引用CSS来渲染样式,而是使用style,或者将样式放在当前页面的<style></style>中

方法一、

1、引用的jar包

<dependency>

  <groupId>org.apache.poi</groupId>

  <artifactId>poi</artifactId>

  <version>4.1.0</version>

</dependency>

2、核心代码

String html = "<div>测试内容</div";

POIFSFileSystem poifs = null;

FileOutputStream ostream = null;

ByteArrayInputStream bais = null;

String uuid = "测试.doc";

File file = null;

try {

  //HTML内容必须被<html><body></body></html>包装

  fileParam.setcContent("<html><body>" + html + "</body></html>");

  byte[] b = fileParam.getcContent().getBytes();

  bais = new ByteArrayInputStream(b);

  poifs = new POIFSFileSystem();

  DirectoryEntry directory = poifs.getRoot();

  //WordDocument名称不允许修改

  directory.createDocument("WordDocument", bais);

  ostream = new FileOutputStream(uuid);

  poifs.writeFilesystem(ostream);//当前目录下就生成了一个测试.doc的文档

} catch (Exception e) {

  logger.error("exception is {}", e);

} finally {

  IOUtils.closeQuietly(poifs);

  IOUtils.closeQuietly(ostream);

  IOUtils.closeQuietly(bais);

  try {

    FileUtils.forceDelete(file);

  } catch (Exception e2) {

  }

}

方法二

 /**
     * word格式html的标签头
     */
    public static final String HTML_TAG_BGN = "<html xmlns=\"http://www.w3.org/TR/REC-html40\" xmlns:v=\"urn:schemas-microsoft-com:vml\" xmlns:o=\"urn:schemas-microsoft-com:office:office\" xmlns:w=\"urn:schemas-microsoft-com:office:word\" xmlns:m=\"http://schemas.microsoft.com/office/2004/12/omml\"><head><meta name=\"ProgId\" content=\"Word.Document\" /><meta name=\"Generator\" content=\"Microsoft Word 12\" /><meta name=\"Originator\" content=\"Microsoft Word 12\" /> <!--[if gte mso 9]><xml><w:WordDocument><w:View>Print</w:View></w:WordDocument></xml><[endif]-->";
    

public filePath downloadWordReport(String htmlForPrint) {
        try {
            String wordString = htmlForPrint.replaceAll("<head>", "").replaceAll("<html>", HTML_TAG_BGN );
            String fileName = new String("测试文件.doc".getBytes(), "UTF-8");
            //上传文件方法
            return this.upload(new ByteArrayInputStream(wordString.getBytes()), fileName);

        } catch (Exception e) {
            return null;
        }
    }