lua 根据路径获取文件名

require "lfs"

function dirpath(path)
    for file in lfs.dir(path) do   --  lfs.dir  根据路径获取该路径下的文件名
        if file ~= '.' and file ~= '..' then
            local f = (path .. '/'..file)
            local attr = lfs.attributes(f) -- 该文件的各种属性
            if attr.mode == "directory" then
                print(f .. "  -->  " .. attr.mode)
                dirpath(f)
            else
                print(f .. "  -->  " .. attr.mode)
            end

        end
    end
end
dirpath("/usr")

删除文件： os.remove(filepath)

文件属性   lfsattributes(filepath) 具体参数有下：

modification    1546497033
rdev    0
size    24
ino     4106061
mode    file
access  1559786365
blocks  8
nlink   1
uid     0
blksize 4096
gid     0
permissions     rw-r--r--
dev     51714
change  1546497033