[LeetCode] 412. Fizz Buzz 嘶嘶嗡嗡

2021年09月15日 阅读数:1
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Write a program that outputs the string representation of numbers from 1 to n.html

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.java

Example:python

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

很简单的一道题,最基本的思路就是对1~n的每个数对3,5取模,根据状况写入结果。而后就是有一些极简的写法和思路,能够看看大牛们的写法,也挺受用的。app

Java:  Not use '%' operationpost

public class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> ret = new ArrayList<String>(n);
        for(int i=1,fizz=0,buzz=0;i<=n ;i++){
            fizz++;
            buzz++;
            if(fizz==3 && buzz==5){
                ret.add("FizzBuzz");
                fizz=0;
                buzz=0;
            }else if(fizz==3){
                ret.add("Fizz");
                fizz=0;
            }else if(buzz==5){
                ret.add("Buzz");
                buzz=0;
            }else{
                ret.add(String.valueOf(i));
            }
        } 
        return ret;
    }
}

Java:url

public class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> list = new ArrayList<>();
        for (int i = 1; i <= n; i++) {
            if (i % 3 == 0 && i % 5 == 0) {
                list.add("FizzBuzz");
            } else if (i % 3 == 0) {
                list.add("Fizz");
            } else if (i % 5 == 0) {
                list.add("Buzz");
            } else {
                list.add(String.valueOf(i));
            }
        }
        return list;
    }
}  

Python:htm

def fizzBuzz(self, n):
    return ['Fizz' * (not i % 3) + 'Buzz' * (not i % 5) or str(i) for i in range(1, n+1)]

Python:  blog

class Solution(object):
    def fizzBuzz(self, n):
        """
        :type n: int
        :rtype: List[str]
        """
        return [str(i) if (i%3!=0 and i%5!=0) else (('Fizz'*(i%3==0)) + ('Buzz'*(i%5==0))) for i in range(1,n+1)]   

Python:three

def fizzBuzz(self, n):
        return ['FizzBuzz'[i % -3 & -4:i % -5 & 8 ^ 12] or repr(i) for i in range(1, n + 1)]

Python:ip

class Solution(object):
    def fizzBuzz(self, n):
        """
        :type n: int
        :rtype: List[str]
        """
        result = []
        for i in xrange(1, n+1):
            if i % 15 == 0:
                result.append("FizzBuzz")
            elif i % 5 == 0:
                result.append("Buzz")
            elif i % 3 == 0:
                result.append("Fizz")
            else:
                result.append(str(i))

        return result

Python:  

class Solution(object):
    def fizzBuzz(self, n):
        """
        :type n: int
        :rtype: List[str]
        """
        l = [str(x) for x in range(n + 1)]
        l3 = range(0, n + 1, 3)
        l5 = range(0, n + 1, 5)
        for i in l3:
            l[i] = 'Fizz'
        for i in l5:
            if l[i] == 'Fizz':
                l[i] += 'Buzz'
            else:
                l[i] = 'Buzz'
        return l[1:] 

Python: wo

class Solution(object):
    def fizzBuzz(self, n):
        """
        :type n: int
        :rtype: List[str]
        """
        res = []
        for i in xrange(1, n + 1):
            if i % 3 == 0 and i % 5 == 0:
                res.append('FizzBuzz')
            elif i % 3 == 0:
                res.append('Fizz')
            elif i % 5 == 0:
                res.append('Buzz')
            else:
                res.append(str(i))
                
        return res  

C++:

class Solution {
public:
    vector<string> fizzBuzz(int n) {
        vector<string> res;
        for (int i = 1; i <= n; ++i) {
            if (i % 15 == 0) res.push_back("FizzBuzz");
            else if (i % 3 == 0) res.push_back("Fizz");
            else if (i % 5 == 0) res.push_back("Buzz");
            else res.push_back(to_string(i));
        }
        return res;
    }
};

  

  

 

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